An infinitely long straight wire carrying current I, one side opened rectangular loop and a conductor C with a sliding connector are located in the same plane, as shown in the figure. The connector has length l. and

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Correct answer: D. μ _ 0 2π (Ivℓ)/(Rr)

The induced current in the wire will be due to the motional EMF developed in the moving resistor and that back emf developed at that point will be equal to $VBL$

$V =$ velocity of the conductor

$B =$ perpendicular magnetic field

$L =$ length of conductor

We know magnetic field due to a long wire is

$B = \dfrac{{\mu}_{0}i}{2\pir}$

Hence the induced current across wire will be :

$I = \dfrac{e}{R}$

$I = \dfrac{{\mu}_{0}}{2\pi}\dfrac{Ivℓ}{Rr}$

An infinitely long straight wire carrying current I, one side...

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