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JEE Main 20207 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2020 · 7 January · Morning Shift · Physics · Electromagnetic Induction

Consider a circular coil of wire carrying constant current I,...

Consider a circular coil of wire carrying constant current I,I, forming a magnetic dipole. The magnetic flux through an infinite plane that contains the circular coil and excluding the circular coil area is given by ϕi{ϕ}_{i} The magnetic flux through the area of the circular coil area is given by ϕ0{ϕ}_{0} . Which of the following option is correct?

Options

  1. Aϕi=ϕ0{ϕ}_{i} = {ϕ}_{0}
  2. Bϕi>ϕ0{ϕ}_{i} > {ϕ}_{0}
  3. Cϕi<ϕ0{ϕ}_{i} < {ϕ}_{0}
  4. Dϕi=−ϕ0{ϕ}_{i} = - {ϕ}_{0}

Correct answer

D. ϕi=−ϕ0{ϕ}_{i} = - {ϕ}_{0}

Step-by-step solution

As magnetic field lines always form a closed loop, hence every magnetic field line creating magnetic flux in the inner region must be passing through the outer region. Since flux in two regions are in opposite direction.
∴ϕi=−ϕ0∴ {ϕ}_{i} = - {ϕ}_{0}
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