A loop ABCDEFA of straight edges has six corner points A (0, 0, 0), B (5, 0, 0), C(5, 5, 0), D(0, 5, 0), E(0, 5, 5) and F(0, 0, 5) . The magnetic field in this region is → B = (3 ^ i + 4 ^ k )T . The quantity of flux

Correct answer: 0 ϕ = → B . → A = (3 ^ i + 4 ^ k ) . (25 ^ i + 25 ^ k ) ϕ = (2 × 25) + (4 × 25) = 175weber

JEE Main 20207 JanuaryMorning Shift

JEE Main 2020 · 7 January · Morning Shift · Physics · Electromagnetic Induction

A loop ABCDEFA of straight edges has six corner points A (0, 0, 0),...

A loop

ABCDEFA

of straight edges has six corner points

A

\left(0, 0, 0\right), B

\left(5, 0, 0\right), C\left(5, 5, 0\right), D\left(0, 5, 0\right), E\left(0, 5, 5\right)

and $

F\left(0, 0, 5\right)

. The magnetic field in this region is

\overset{\to}{B} =

\left(3\overset{^}{i} + 4\overset{^}{k}\right)T

. The quantity of flux through the loop

ABCDEFA

(in

Wb$ ) is _____________ A loop ABCDEFA of straight edges has six corner points A (0, 0, 0), B (5, 0, 0), C(5, 5, 0), D(0, 5, 0), E(0, 5, 5) and

ϕ = \overset{\to}{B} . \overset{\to}{A} = \left(3\overset{^}{i} + 4\overset{^}{k}\right) . \left(25\overset{^}{i} + 25\overset{^}{k}\right)

ϕ = \left(2 \times 25\right) + \left(4 \times 25\right) = 175weber