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JEE Main20207 Jan 2020Morning ShiftPhysicsElectromagnetic InductionActual

A loop A B C D E F A of straight edges has six corner points A 0 , 0 , 0 , B 5 , 0 , 0 , C 5 , 5 , 0 , D 0 , 5 , 0 , E 0 , 5 , 5 and F 0 , 0 , 5 . The magnetic field in this region is B → = 3 i ^ + 4 k ^ T . The quantity of flux through the loop A B C D E F A (in W b ) is _____________

Correct answer

0

Step-by-step solution

ϕ = B → . A → = 3 i ^ + 4 k ^ . 25 i ^ + 25 k ^ ϕ = 2 × 25 + 4 × 25 = 175 w e b e r

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