JEE Main20207 Jan 2020Morning ShiftPhysicsElectromagnetic InductionActual
A loop A B C D E F A of straight edges has six corner points A 0 , 0 , 0 , B 5 , 0 , 0 , C 5 , 5 , 0 , D 0 , 5 , 0 , E 0 , 5 , 5 and F 0 , 0 , 5 . The magnetic field in this region is B → = 3 i ^ + 4 k ^ T . The quantity of flux through the loop A B C D E F A (in W b ) is _____________
Correct answer
0
Step-by-step solution
ϕ = B → . A → = 3 i ^ + 4 k ^ . 25 i ^ + 25 k ^ ϕ = 2 × 25 + 4 × 25 = 175 w e b e r