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JEE Main 201816 AprilOnline
Exam
JEE Main
Year
2018
Date
16 April
Mode
Online
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2018 · 16 April · Online · Physics · Electromagnetic Induction

A coil of cross-sectional area A having n turns is placed in a...

A coil of cross-sectional area AA having nn turns is placed in a uniform magnetic field BB. When it is rotated with an angular velocity ω,\omega , the maximum e.m.f. induced in the coil will be:

Options

  1. A32nBAω\dfrac{3}{2}nBA\omega
  2. B3nBAω3nBA\omega
  3. CnBAωnBA\omega
  4. D12nBAω\dfrac{1}{2}nBA\omega

Correct answer

C. nBAωnBA\omega

Step-by-step solution

Magnetic flux through a coil of area AA of nn turns at an angle θ\theta to the magnetic field of magnitude BB is, ϕ=nBAcosθ=nBAcos\omegat\phi = nBAcos\theta = nBAcos\omegat. The induced emf,

ε=∣dϕdt∣=nBAωsin\omegatε = \left|\dfrac{dϕ}{dt}\right| = nBA\omega sin \omegat. Since, the maximum value of the sine function is 11,

{ε}_\max = nBA\omega

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