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JEE Main 201219 MayOnline
Exam
JEE Main
Year
2012
Date
19 May
Mode
Online
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2012 · 19 May · Online · Physics · Electromagnetic Induction

This question has Statement 1 and Statement 2. Of the four choices...

This question has Statement 1 and Statement 2. Of the four choices given after the Statements, choose the one that best describes the two Statements. Statement 1: Self inductance of a long solenoid of length LL, total number of turns N\mathrm{N} and radius r\mathrm{r} is less than πμ0N2r2L\frac{\pi \mu_0 N^2 r^2}{L}. Statement 2: The magnetic induction in the solenoid in Statement 1 carrying current II is μ0NIL\frac{\mu_0 N I}{L} in the middle of the solenoid but becomes less as we move towards its ends.

Options

  1. AStatement 1 is true, Statement 2 is false.
  2. BStatement 1 is true, Statement 2 is true, Statement 2 is the correct explanation of Statement 1.
  3. CStatement 1 is false, Statement 2 is true.
  4. DStatement 1 is true, Statement 2 is true, Statement 2 is not the correct explanation of Statement 1.

Correct answer

B. Statement 1 is true, Statement 2 is true, Statement 2 is the correct explanation of Statement 1.

Step-by-step solution

Self inductance of a long solenoid is given by L=μ0N2Al\frac{\mu_0 N^2 A}{l}Magnetic field at the centre of solenoid B=μ0NIl\frac{\mu_0 N I}{l}So both the statements are correct and statement 2 is correct explanation of statement 1
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