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JEE Main 201212 MayOnline
Exam
JEE Main
Year
2012
Date
12 May
Mode
Online
Subject
Physics
Chapter
Electromagnetic Induction

JEE Main 2012 · 12 May · Online · Physics · Electromagnetic Induction

Magnetic flux through a coil of resistance 10 is changed by Δ φ in...

Magnetic flux through a coil of resistance 10Ω10 \Omega is changed by Δϕ\Delta \phi in 0.1 s0.1 \mathrm{~s}. The resulting current in the coil varies with time as shown in the figure. Then ∣Δϕ∣|\Delta \phi| is equal to (in weber) Magnetic flux through a coil of resistance 10 is changed by Δ φ in 0.1 ~s . The resulting current in the coil varies

Options

  1. A6
  2. B4
  3. C2
  4. D8

Correct answer

C. 2

Step-by-step solution

 As \text{ As }e=ΔϕΔt or Ri=ΔϕΔt(\becausee=Ri)⇒Δϕ=R(i.Δt)=R× area under i−t graph =10×12×4×0.1=2 weber \begin{aligned}e=\frac{\Delta \phi}{\Delta t}& \text{ or }R i=\frac{\Delta \phi}{\Delta t} \quad(\becausee=R i) \\ \Rightarrow \quad \Delta \phi& =R(i . \Delta t) \\ & =R \times \text{ area under }i-t \text{ graph }\\ = & 10 \times \frac{1}{2} \times4 \times0.1=2 \text{ weber } \end{aligned}$$
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