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JEE Main 202430 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
30 January
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2024 · 30 January · Evening Shift · Physics · Electromagnetic Waves

Match List I with List II List I List II A. Gauss’s law of...

Match List I with List II

  List I   List II
A. Gauss’s law of magnetostatics i. ∮E→⋅da→=1ε0∫ρdV∮ \overset{\to}{E} \cdot d\overset{\to}{a} = \dfrac{1}{{ε}_{0}} ∫ ρdV
B. Faraday’s law of electro magnetic induction ii. ∮B→⋅da→=0∮ \overset{\to}{B} \cdot d\overset{\to}{a} = 0
C. Ampere’s law iii. ∮E→⋅dl→=−ddt∫B→⋅da→∮ \overset{\to}{E} \cdot d\overset{\to}{l} = \dfrac{- d}{dt} ∫ \overset{\to}{B} \cdot d\overset{\to}{a}
D. Gauss’s law of electrostatics iv. ∮B→⋅dl→=μ0I∮ \overset{\to}{B} \cdot d\overset{\to}{l} = {\mu}_{0}I

Choose the correct answer from the options given below:

Options

  1. AA-I, B-III, C-IV, D-II
  2. BA-III, B-IV, C-I, D-II
  3. CA-IV, B-II, C-III, D-I
  4. DA-II, B-III, C-IV, D-I

Correct answer

D. A-II, B-III, C-IV, D-I

Step-by-step solution

Gauss’s law of magnetostatics:

∮B→⋅da→=0∮ \overset{\to}{B} \cdot d\overset{\to}{a} = 0

Faraday’s law of electro magnetic induction:

∮E→⋅dl→=−ddt∫B→⋅da→∮ \overset{\to}{E} \cdot d\overset{\to}{l} = \dfrac{- d}{dt} ∫ \overset{\to}{B} \cdot d\overset{\to}{a}

Ampere’s law:

∮B→⋅dl→=μ0I∮ \overset{\to}{B} \cdot d\overset{\to}{l} = {\mu}_{0}I

Gauss’s law of electrostatics:

∮E→⋅da→=1ε0∫ρdV∮ \overset{\to}{E} \cdot d\overset{\to}{a} = \dfrac{1}{{ε}_{0}} ∫ ρdV

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