JEE Main 202430 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 30 January
- Shift
- Morning Shift
- Subject
- Physics
- Chapter
- Electromagnetic Waves
JEE Main 2024 · 30 January · Morning Shift · Physics · Electromagnetic Waves
The electric field of an electromagnetic wave in free space is...
The electric field of an electromagnetic wave in free space is represented as \overset{\to}{E} = {E}_{0}\cos ( \omegat - kz ) \overset{^}{i}. The corresponding magnetic induction vector will be :
Options
- A\overset{\to}{B} = {E}_{0}Ccos ( \omegat - kz ) \overset{^}{j}
- B\overset{\to}{B} = \dfrac{{E}_{0}}{C}\cos ( \omegat - kz ) \overset{^}{j}
- C\overset{\to}{B} = {E}_{0}Ccos ( \omegat + kz ) \overset{^}{j}
- D\overset{\to}{B} = \dfrac{{E}_{0}}{C}\cos ( \omegat + kz ) \overset{^}{j}
Correct answer
B. \overset{\to}{B} = \dfrac{{E}_{0}}{C}\cos ( \omegat - kz ) \overset{^}{j}
Step-by-step solution
Given \overset{\to}{E} = {E}_{0}\cos ( \omegat - kz ) \overset{^}{i}:
Clearly, term represents, electromagnetic wave is travelling along direction or along \overset{^}{k}.
Now, in vector form, direction of electromagnetive wave is given by \overset{^}{C} = \overset{^}{E} \times \overset{^}{B}. Therefore, magnetic field is along \overset{^}{j}.
Also, we know that , where is speed of light.
Therefore, \overset{\to}{B} = \dfrac{{E}_{0}}{C}\cos ( \omegat - kz ) \overset{^}{j}.