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JEE Main 202427 JanuaryEvening Shift
Exam
JEE Main
Year
2024
Date
27 January
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2024 · 27 January · Evening Shift · Physics · Electromagnetic Waves

An object is placed in a medium of refractive index 3 . An...

An object is placed in a medium of refractive index 33. An electromagnetic wave of intensity 6×108Wm−26 \times {10}^{8}W{m}^{- 2} falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space =3×108ms−1= 3 \times {10}^{8}m{s}^{- 1} ):

Options

  1. A36Nm−236N{m}^{- 2}
  2. B18Nm−218N{m}^{- 2}
  3. C6Nm−26N{m}^{- 2}
  4. D2Nm−22N{m}^{- 2}

Correct answer

C. 6Nm−26N{m}^{- 2}

Step-by-step solution

The formula to calculate the radiation pressure is given by

P=Iv...(1)P = \dfrac{I}{v} . . . \left(1\right)

Also, the velocity of the electromagnetic wave can be expressed as

μ=cv...(2)\mu = \dfrac{c}{v} . . . \left(2\right)

Equations (1) and (2) imply that

{P=I⋅μc=6×108×33×108=6Nm−2\begin{cases}P & = & \dfrac{I \cdot \mu}{c} \\ & = & \dfrac{6 \times {10}^{8} \times 3}{3 \times {10}^{8}} \\ & = & 6N{m}^{- 2}\end{cases}

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