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JEE Main 202427 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
27 January
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2024 · 27 January · Morning Shift · Physics · Electromagnetic Waves

A plane electromagnetic wave propagating in x -direction is...

A plane electromagnetic wave propagating in xx-direction is described by
Ey={E}_{y} =\left(200V{m}^{- 1}\right)sin[1.5×107t−0.05x];\left[1 . 5 \times {10}^{7}t - 0 . 05x\right];The intensity of the wave is :
(Use ϵ0=8.85×10−12C2N−1m−2{ϵ}_{0} = 8 . 85 \times {10}^{- 12}{C}^{2}{N}^{- 1}{m}^{- 2})

Options

  1. A35.4Wm−235 . 4W{m}^{- 2}
  2. B53.1Wm−253 . 1W{m}^{- 2}
  3. C26.6Wm−226 . 6W{m}^{- 2}
  4. D106.2Wm−2106 . 2W{m}^{- 2}

Correct answer

B. 53.1Wm−253 . 1W{m}^{- 2}

Step-by-step solution

The magnitude of the electric field component of the electromagnetic wave is given by

E0=200Vm−1{E}_{0} = 200V{m}^{- 1}

The formula to calculate the intensity of the electromagnetic wave is given by

I=12ε0cE02...(1)I = \dfrac{1}{2}{ε}_{0}c{E}_{0}^{2} . . . \left(1\right)

From equation (1), it follows that

{I=12×8.85×10−12×3×108×(200)2Wm−2=53.1Wm−2\begin{cases}I & = & \dfrac{1}{2} \times 8 . 85 \times {10}^{- 12} \times 3 \times {10}^{8} \times {\left(200\right)}^{2}W{m}^{- 2} \\ & = & 53 . 1W{m}^{- 2}\end{cases}

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