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JEE Main 20208 JanuaryEvening Shift
Exam
JEE Main
Year
2020
Date
8 January
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2020 · 8 January · Evening Shift · Physics · Electromagnetic Waves

A plane electromagnetic wave of frequency 25GHz is propagating in...

A plane electromagnetic wave of frequency 25GHz25GHz is propagating in vacuum along the z-direction. At a particular point in space and time, the magnetic filed is given by \overset{\to}{B} = 5 \times {10}^{- 8}\overset{^}{j}T . The corresponding electric field E→\overset{\to}{E} is (speed of light =3×108ms−1= 3 \times {10}^{8}m{s}^{- 1} )

Options

  1. A1.66 \times {10}^{- 16}\overset{^}{i}\dfrac{V}{m}
  2. B- 1.66 \times {10}^{- 16}\overset{^}{i}\dfrac{V}{m}
  3. C- 15\overset{^}{i}\dfrac{V}{m}
  4. D15\overset{^}{i}\dfrac{V}{m}

Correct answer

D. 15\overset{^}{i}\dfrac{V}{m}

Step-by-step solution

Given, the electromagnetic wave is propagating in zz i.e., + \overset{^}{k} direction.

The relation between the magnitudes of electric field, magnetic field and the speed of light is given by

∣E∣∣B∣=C\dfrac{\left|E\right|}{\left|B\right|} = C

⇒∣E∣=∣B∣×C⇒ \left|E\right| = \left|B\right| \times C
⇒∣E∣=5×10−8×3×108=15Vm−1⇒ \left|E\right| = 5 \times {10}^{- 8} \times 3 \times {10}^{8} = 15V{m}^{- 1}

We know that the direction of propagation of electromagnetic wave is along E→×B→\overset{\to}{E} \times \overset{\to}{B}.

So, \overset{\to}{E} = 15\overset{^}{i}V{m}^{- 1}

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