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JEE Main20207 Jan 2020Morning ShiftPhysicsElectromagnetic WavesActual

If the magnetic field in a plane electromagnetic wave is given by B → = 3 × 10 - 8 sin ⁡ 1.6 × 10 3 x + 48 × 10 10 t j ^ T , then what will be expression for electric field ?

Options

  1. AE → = 60 sin ⁡ 1.6 × 10 3 x + 48 × 10 10 t k ^ V m
  2. BE → = 9 sin ⁡ 1.6 × 10 3 x + 48 × 10 10 t k ^ V m
  3. CE → = 3 × 10 - 8 sin ⁡ 1.6 × 10 3 x + 48 × 10 10 t j ^ V m
  4. DE → = 3 × 10 - 8 sin ⁡ 1.6 × 10 3 x + 48 × 10 10 t i ^ V m

Correct answer

B. E → = 9 sin ⁡ 1.6 × 10 3 x + 48 × 10 10 t k ^ V m

Step-by-step solution

E 0 B 0 = C (speed of light in vacuum) E 0 = B 0 C = 3 × 10 - 8 × 3 × 10 8 = 9 N C So, E = 9 sin ⁡ ω t + k x + ϕ E → = 9 sin ⁡ 1.6 × 10 3 x + 48 × 10 10 t k   ^ V m

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