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JEE Main 20198 AprilMorning Shift
Exam
JEE Main
Year
2019
Date
8 April
Shift
Morning Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2019 · 8 April · Morning Shift · Physics · Electromagnetic Waves

A plane electromagnetic wave travels in free space along the...

A plane electromagnetic wave travels in free space along the x-direction. The electric field component of the wave at a particular point of space and time is E=6Vm−1E = 6V{m}^{- 1} along y-direction. Its corresponding magnetic field component, BB would be:

Options

  1. A2×10−8T2 \times {10}^{- 8}T along z-direction
  2. B2×10−8T2 \times {10}^{- 8}T  along y-direction
  3. C6×10−8T6 \times {10}^{- 8}T  along z-direction
  4. D6×10−8T6 \times {10}^{- 8}T  along x-direction

Correct answer

A. 2×10−8T2 \times {10}^{- 8}T along z-direction

Step-by-step solution

B=EC=63×108=2×10−8TB = \dfrac{E}{C} = \dfrac{6}{3 \times {10}^{8}} = 2 \times {10}^{- 8}T
E→×B→\overset{\to}{E} \times \overset{\to}{B} is along xx -direction
\overset{^}{j} \times \left(a\overset{^}{i} + b\overset{^}{j} + c\overset{^}{k}\right) = \overset{^}{i}
c=1c = 1
B→\overset{\to}{B} is along \overset{^}{k}
B=2×10−8TB = 2 \times {10}^{- 8}T along zz -direction
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