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JEE Main 20199 JanuaryEvening Shift
Exam
JEE Main
Year
2019
Date
9 January
Shift
Evening Shift
Subject
Physics
Chapter
Electromagnetic Waves

JEE Main 2019 · 9 January · Evening Shift · Physics · Electromagnetic Waves

The energy associated with electric field is ( U _ E ) and with...

The energy associated with electric field is (UE)\left({U}_{E}\right) and with magnetic field is (UB)\left({U}_{B}\right) for an electromagnetic wave in free space. Then:

Options

  1. AUE>UB{U}_{E} > {U}_{B}
  2. BUE=UB{U}_{E} = {U}_{B}
  3. CUE=UB2{U}_{E} = \dfrac{{U}_{B}}{2}
  4. DUE<UB{U}_{E} < {U}_{B}

Correct answer

B. UE=UB{U}_{E} = {U}_{B}

Step-by-step solution

The average energy density of electric field is given by

uE=12εE02{u}_{E} = \dfrac{1}{2}ε{{E}_{0}}^{2}

Here, E0{E}_{0} is the maximum value of electric field.

The average energy density of magnetic field is given by

uB=B022μ{u}_{B} = \dfrac{{{B}_{0}}^{2}}{2\mu}

Here, B0{B}_{0} is the maximum value of magnetic field.

The speed of light is given by c2=1με{c}^{2} = \dfrac{1}{\muε}

Also, E0=cB0{E}_{0} = c{B}_{0}

So, uE=12c2μ(cB0)2=B022μ=uB{u}_{E} = \dfrac{1}{2{c}^{2}\mu}{\left(c{B}_{0}\right)}^{2} = \dfrac{{{B}_{0}}^{2}}{2\mu} = {u}_{B}

As the energy density of electric field and magnetic field are equal, the energy associated for equal volume will also be equal.

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