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JEE Main 20199 JanuaryMorning Shift

Exam: JEE Main
Year: 2019
Date: 9 January
Shift: Morning Shift
Subject: Physics
Chapter: Electromagnetic Waves

JEE Main 2019 · 9 January · Morning Shift · Physics · Electromagnetic Waves

A plane electromagnetic wave of frequency 50MHz travels in free...

A plane electromagnetic wave of frequency

50MHz

travels in free space along the positive

x

- direction. At a particular point in space and time,

\overset{\to}{E} = 6.3\overset{^}{j}V / m,

The corresponding magnetic field

\overset{\to}{B,}

at that point will be:

Options

A $2.1 \times {10}^{- 8}\overset{^}{k}T$
B $18.9 \times {10}^{8}\overset{^}{k}T$
C $18.9 \times {10}^{- 8}\overset{^}{k}T$
D $6.3 \times {10}^{- 8}\overset{^}{k}T$

Correct answer

A. $2.1 \times {10}^{- 8}\overset{^}{k}T$

Step-by-step solution

As we know

\dfrac{E}{B} = C

E = 6.3V / m

B = \dfrac{E}{C} = \dfrac{6.3}{3 \times {10}^{8}}T = 2.1 \times {10}^{- 8}T

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