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JEE Main 202624 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
24 January
Shift
Morning Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2026 · 24 January · Morning Shift · Physics · Electrostatics

Three charges +2 q,+3 q and -4 q are situated at (0,-3 a),(2 a, 0)...

Three charges +2q,+3q+2 q,+3 q and −4q-4 q are situated at (0,−3a),(2a,0)(0,-3 a),(2 a, 0) and (−2a,0)(-2 a, 0) respectively in the xyx y plane. The resultant dipole moment about origin is ____\_\_\_\_.

Options

  1. A2qa(7i^−3j^)2 q a(7 \hat{i}-3 \hat{j})
  2. B2qa(3j^−i^)2 q a(3 \hat{j}-\hat{i})
  3. C2qa(3i^−7j^)2 q a(3 \hat{i}-7 \hat{j})
  4. D2qa(3j^−7i^)2 q a(3 \hat{j}-7 \hat{i})

Correct answer

A. 2qa(7i^−3j^)2 q a(7 \hat{i}-3 \hat{j})

Step-by-step solution

The dipole moment is given by:
p⃗=q1r⃗1+q2r⃗2+q3r⃗3\vec{p} = q_1\vec{r}_1 + q_2\vec{r}_2 + q_3\vec{r}_3
p⃗=(2q)(−3a)j^+(3q)(2a)i^+(−4q)(−2a)i^\vec{p} = (2q)(-3a)\hat{j} + (3q)(2a)\hat{i} + (-4q)(-2a)\hat{i}
p⃗=−6qaj^+6qai^+8qai^\vec{p} = -6qa\hat{j} + 6qa\hat{i} + 8qa\hat{i}
p⃗=14qai^−6qaj^\vec{p} = 14qa\hat{i} - 6qa\hat{j}
p⃗=2qa(7i^−3j^)\vec{p} = 2qa(7\hat{i} - 3\hat{j})
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