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JEE Main 202624 JanuaryMorning Shift
Exam
JEE Main
Year
2026
Date
24 January
Shift
Morning Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2026 · 24 January · Morning Shift · Physics · Electrostatics

There are three co-centric conducting spherical shells A, B and C...

There are three co-centric conducting spherical shells A,BA, B and CC of radii a,ba, b and cc respectively (c>b>a)(c>b>a) and they are charged with charge q1,q2q_{1}, q_{2} and q3q_{3} respectively. The potentials of the spheres A,BA, B and CC respectively, are :

Options

  1. A\frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}+q_{3}}{a}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}+q_{3}}{b}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}+q_{3}}{c}\right)
  2. B\frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}}{a}+\frac{q_{2}}{b}+\frac{q_{3}}{c}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}+q_{3}}{b}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}+q_{3}}{c}\right)
  3. C\frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}}{a}+\frac{q_{2}}{b}+\frac{q_{3}}{c}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}}{b}+\frac{q_{3}}{c}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}+q_{3}}{c}\right)
  4. D\frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}+q_{3}}{a}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}}{b}+\frac{q_{3}}{c}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}}{a}+\frac{q_{2}}{b}+\frac{q_{3}}{c}\right)

Correct answer

C. \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}}{a}+\frac{q_{2}}{b}+\frac{q_{3}}{c}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}}{b}+\frac{q_{3}}{c}\right), \frac{1}{4 \pi \epsilon_{\mathrm{o}}}\left(\frac{q_{1}+q_{2}+q_{3}}{c}\right)

Step-by-step solution

The potential at any point due to a charged spherical shell of radius RR and charge QQ is V=14πϵoQRV = \frac{1}{4\pi\epsilon_o} \frac{Q}{R} for points inside or on the surface (r≤Rr \le R), and V=14πϵoQrV = \frac{1}{4\pi\epsilon_o} \frac{Q}{r} for points outside (r>Rr > R).
Let k=14πϵok = \frac{1}{4\pi\epsilon_o}. The potentials of the three shells A,B,CA, B, C with radii a<b<ca < b < c and charges q1,q2,q3q_1, q_2, q_3 are calculated by superposition.
For shell AA (r=ar = a):
Shell AA is on its own surface, while it is inside shells BB and CC.
VA=kq1a+kq2b+kq3c=14πϵo(q1a+q2b+q3c)V_A = k\frac{q_1}{a} + k\frac{q_2}{b} + k\frac{q_3}{c} = \frac{1}{4\pi\epsilon_o} \left( \frac{q_1}{a} + \frac{q_2}{b} + \frac{q_3}{c} \right)
For shell BB (r=br = b):
Shell BB is outside shell AA, on its own surface, and inside shell CC.
VB=kq1b+kq2b+kq3c=14πϵo(q1+q2b+q3c)V_B = k\frac{q_1}{b} + k\frac{q_2}{b} + k\frac{q_3}{c} = \frac{1}{4\pi\epsilon_o} \left( \frac{q_1 + q_2}{b} + \frac{q_3}{c} \right)
For shell CC (r=cr = c):
Shell CC is outside shells AA and BB, and on its own surface.
VC=kq1c+kq2c+kq3c=14πϵo(q1+q2+q3c)V_C = k\frac{q_1}{c} + k\frac{q_2}{c} + k\frac{q_3}{c} = \frac{1}{4\pi\epsilon_o} \left( \frac{q_1 + q_2 + q_3}{c} \right)
Comparing these expressions with the given options, option (3) matches correctly.
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