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JEE Main 202528 JanuaryMorning Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Morning Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2025 · 28 January · Morning Shift · Physics · Electrostatics

A particle of mass ' m ' and charge ' q ' is fastened to one end '...

A particle of mass ' mm ' and charge ' qq ' is fastened to one end ' AA ' of a massless string having equilibrium length ll, whose other end is fixed at point ' OO '. The whole system is placed on a frictionless horizontal plane and is initially at rest. If uniform electric field is switched on along the direction as shown in figure, then the speed of the particle when it crosses the x -axis is A particle of mass ' m ' and charge ' q ' is fastened to one end ' A ' of a massless string having equilibrium length l

Options

  1. AqEl2 m\sqrt{\frac{\mathrm{qE} l}{2 \mathrm{~m}}}
  2. BqEl m\sqrt{\frac{\mathrm{qE} l}{\mathrm{~m}}}
  3. CqEl4 m\sqrt{\frac{\mathrm{qE} l}{4 \mathrm{~m}}}
  4. D2qElm\sqrt{\frac{2 q \mathrm{El}}{\mathrm{m}}}

Correct answer

B. qEl m\sqrt{\frac{\mathrm{qE} l}{\mathrm{~m}}}

Step-by-step solution

A particle of mass ' m ' and charge ' q ' is fastened to one end ' A ' of a massless string having equilibrium length l
Wall=ΔkWe=kf−kiqEℓ2=12mv2−0v=qEℓm\begin{aligned} & \mathrm{W}_{\mathrm{all}}=\Delta \mathrm{k} \\ & \mathrm{W}_{\mathrm{e}}=\mathrm{k}_{\mathrm{f}}-\mathrm{k}_{\mathrm{i}} \\ & \mathrm{qE} \frac{\ell}{2}=\frac{1}{2} \mathrm{mv}^2-0 \\ & \mathrm{v}=\sqrt{\frac{\mathrm{qE} \ell}{\mathrm{m}}}\end{aligned}
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