JEE Main202524 Jan 2025Evening ShiftPhysicsElectrostaticsActual
A small uncharged conducting sphere is placed in contact with an identical sphere but having 4 10⁻⁸ C charge and then removed to a distance such that the force of repulsion between them is 9 10⁻³ ~N . The distance between them is (Take 1 4 _ o as 9 10^9 in SI units)
Options
- A3 cm
- B2 cm
- C4 cm
- D1 cm
Correct answer
B. 2 cm
Step-by-step solution
aligned & F = k ( 2 ) ( 2 ) r ^2 & 9 10⁻³= 9 10^9 (4 10⁻⁸ ) 4 10⁻⁸ 4 r ^2 & r ^2= 9 10^9 16 10⁻¹⁶ 4 9 10⁻³ =4 10⁻⁴ & r =2 10⁻² ~m 2 ~cm aligned