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JEE Main 202429 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
29 January
Shift
Morning Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2024 · 29 January · Morning Shift · Physics · Electrostatics

Match List I with List II Chose the correct answer from the options...

Match List I with List II

Match List I with List II Chose the correct answer from the options given below

Chose the correct answer from the options given below

Options

  1. AA−IV,B−I,C−III,D−IIA - IV, B - I, C - III, D - II
  2. BA−II,B−III,C−I,D−IVA - II, B - III, C - I, D - IV
  3. CA−IV,B−III,C−I,D−IIA - IV, B - III, C - I, D - II
  4. DA−I,B−II,C−III,D−IVA - I, B - II, C - III, D - IV

Correct answer

C. A−IV,B−III,C−I,D−IIA - IV, B - III, C - I, D - II

Step-by-step solution

Ampere – Maxwell law

→∮B→⋅dl→=μ0ic+μ0ε0dϕEdt\to ∮ \overset{\to}{B} \cdot d\overset{\to}{l} = {\mu}_{0}{i}_{c} + {\mu}_{0}{ε}_{0}\dfrac{d{ϕ}_{E}}{dt}

Faraday law 

→∮E→⋅dl→=dϕBdt\to ∮ \overset{\to}{E} \cdot d\overset{\to}{l} = \dfrac{d{ϕ}_{B}}{dt}

Gauss’ law for electricity →∮E→⋅dA→=Qε0\to ∮ \overset{\to}{E} \cdot d\overset{\to}{A} = \dfrac{Q}{{ε}_{0}}

Gauss' law for magnetism →∮B→⋅dA→=0\to ∮ \overset{\to}{B} \cdot d\overset{\to}{A} = 0

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