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The electric potential at the surface of an atomic nucleus ( Z = 50 ) of radius 9 × 10 - 13 cm is α × 10 6 V . What is the value of α ? (Charge of proton 1 . 6 × 10 - 19 C )

Correct answer

0

Step-by-step solution

The electric potential at the surface of an atomic nucleus can be written as V = k Q R = k · Z e R . . . 1 From equation (1), it follows that V = 9 × 10 9 × 50 × 1 . 6 × 10 - 19 9 × 10 - 13 × 10 - 2 V = 8 × 10 6 V Hence, α = 8 .

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