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JEE Main 202330 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
30 January
Shift
Morning Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2023 · 30 January · Morning Shift · Physics · Electrostatics

Two isolated metallic solid spheres of radii R and 2R are charged...

Two isolated metallic solid spheres of radii RR and 2R2R are charged such that both have same charge density σ\sigma . The spheres are then connected by a thin conducting wire. If the new charge density of the bigger sphere is σ′{\sigma}^{'}. The ratio σ′σ\dfrac{{\sigma}^{'}}{\sigma} is :Two isolated metallic solid spheres of radii R and 2R are charged such that both have same charge density σ . TheTwo isolated metallic solid spheres of radii R and 2R are charged such that both have same charge density σ . The

Options

  1. A94\dfrac{9}{4}
  2. B43\dfrac{4}{3}
  3. C53\dfrac{5}{3}
  4. D56\dfrac{5}{6}

Correct answer

D. 56\dfrac{5}{6}

Step-by-step solution

Charge and charge density on both isolated metallic solid spheres are show below.

Two isolated metallic solid spheres of radii R and 2R are charged such that both have same charge density σ . The

Let the charges and the charge densities on both the spheres after connected by thin conducting wire be Q1′,Q2′,σandσ′{Q}_{1}^{'}, {Q}_{2}^{'}, \sigma\text{and}{\sigma}^{'} as shown below.

Two isolated metallic solid spheres of radii R and 2R are charged such that both have same charge density σ . The

Once connected, charge on both the spheres will redistribute such that potentials at the surface of both spheres is the same.

∴kQ1′R=kQ2′2R∴ \dfrac{k{Q}_{1}^{'}}{R} = \dfrac{k{Q}_{2}^{'}}{2R}

⇒Q1′4πε0R=Q2′4πε0(2R)⇒ {Q}_{1}^{'}4{\pi ε}_{0}R = \dfrac{{Q}_{2}^{'}}{4\pi{ε}_{0}\left(2R\right)}

∴Q2′=2Q1′∴ {Q}_{2}^{'} = 2{Q}_{1}^{'}

Using charge conservation,

Q1′+Q2′=Q1+Q2{Q}_{1}^{'} + {Q}_{2}^{'} = {Q}_{1} + {Q}_{2}

∴Q2′2+Q2′=20πR2σ∴ {Q}_{2}^{'}2 + {Q}_{2}^{'} = 20{\pi R}^{2}\sigma

32Q2′=20πR2σ\dfrac{3}{2}{Q}_{2}^{'} = 20{\pi R}^{2}\sigma

∴Q2′4π(2R)2=23×20πR2σ16πR2∴ {Q}_{2}^{'}4\pi{\left(2R\right)}^{2} = \dfrac{2}{3} \times \dfrac{20{\pi R}^{2}\sigma}{16{\pi R}^{2}}

∴σ′σ=56∴ \dfrac{\sigma '}{\sigma} = \dfrac{5}{6}

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