A point charge 2 × 10 ^ – 2 C is moved from P to S in a uniform...

As electric field is uniform, so force acting on the charged particle will be uniform.

Therefore,

${W}_{E} = \overset{\to}{F} \cdot \overset{\to}{s} = q\overset{\to}{E} \cdot \overset{\to}{s}$

= \left(2 \times {10}^{- 2}\right)\left[30\overset{^}{i} \cdot \left[\left(0\overset{^}{i} + 0\overset{^}{j} + 0\overset{^}{k}\right) - \left(\overset{^}{i} + 2\overset{^}{j} + 0\overset{^}{k}\right)\right]\right]

$= - 60 \times {10}^{- 2}J$

$= - 600mJ$