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JEE Main 202329 JanuaryMorning Shift
Exam
JEE Main
Year
2023
Date
29 January
Shift
Morning Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2023 · 29 January · Morning Shift · Physics · Electrostatics

In a cuboid of dimension 2L × 2L × L , a charge q is placed at the...

In a cuboid of dimension 2L×2L×L2L \times 2L \times L , a charge qq is placed at the centre of the surface SS having area of 4L24{L}^{2} . The flux through the opposite surface to SS is given byIn a cuboid of dimension 2L × 2L × L , a charge q is placed at the centre of the surface S having area of 4 L ^ 2 . The

Options

  1. Aq12∈0\dfrac{q}{12{\in}_{0}}
  2. Bq3∈0\dfrac{q}{3{\in}_{0}}
  3. Cq2∈0\dfrac{q}{2{\in}_{0}}
  4. Dq6∈0\dfrac{q}{6{\in}_{0}}

Correct answer

D. q6∈0\dfrac{q}{6{\in}_{0}}

Step-by-step solution

Assume a similar cuboid on top of the given cuboid to make symmetry about charge. Thus, it becomes a cube of length 2L2L.

In a cuboid of dimension 2L × 2L × L , a charge q is placed at the centre of the surface S having area of 4 L ^ 2 . The

Flux passing through whole cube is ϕ=q∈0ϕ = \dfrac{q}{{\in}_{0}}(Gauss's Law).

Since, total faces are 66, so flux passing through shaded face =q6∈0= \dfrac{q}{6{\in}_{0}}.

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