A point charge q 1 = 4 q 0 is placed at origin. Another point charge q 2 = - q 0 is placed at x = 12 cm . Charge of proton is q 0 . The proton is placed on x -axis so that the electrostatic force on the proton in zero. In this situation, the position of the proton from the origin is ______ cm .

Step-by-step solution

Let at point P net electric field is zero. As direction of electric field due to both charges at point P is opposite, equating magnitude we get 1 4 π ε 0 4 q 0 x 2 = 1 4 π ε 0 q 0 x - 12 2 ⇒ 2 x - 12 = x ⇒ x = 24   cm Distance of proton from origin = 24   cm .