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JEE Main202324 Jan 2023Morning ShiftPhysicsElectrostaticsActual

If two charges q 1 and q 2 are separated with distance d and placed in a medium of dielectric constant k . What will be the equivalent distance between charges in air for the same electrostatic force?

Options

  1. Ad k
  2. Bk d
  3. C1 . 5 d k
  4. D2 d k

Correct answer

A. d k

Step-by-step solution

The force between the two charges when they are placed in dielectric is F 1 = 1 4 π ε o k q 1 q 2   d 2 The force between the two charges when they are placed at separation d ' is F 2 = 1 4 π ε o q 1 q 2   d ' 2   Since, the force between the two charges is same in both case F 1 = F 2 ⇒ 1 4 π ε o k           q 1 q 2   d 2 =   1 4 π ε o   q 1 q 2   d ' 2 ⇒ d ' = d k

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