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JEE Main 202324 JanuaryEvening Shift
Exam
JEE Main
Year
2023
Date
24 January
Shift
Evening Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2023 · 24 January · Evening Shift · Physics · Electrostatics

The electric potential at the centre of two concentric half rings...

The electric potential at the centre of two concentric half rings of radii R1{R}_{1} and R2{R}_{2}, having same linear charge density λ\lambda is

The electric potential at the centre of two concentric half rings of radii R _ 1 and R _ 2 , having same linear charge.

Options

  1. A2λ∈0\dfrac{2\lambda}{{\in}_{0}}
  2. Bλ2∈0\dfrac{\lambda}{2{\in}_{0}}
  3. Cλ4∈0\dfrac{\lambda}{4{\in}_{0}}
  4. Dλ∈0\dfrac{\lambda}{{\in}_{0}}

Correct answer

B. λ2∈0\dfrac{\lambda}{2{\in}_{0}}

Step-by-step solution

The electric potential at the centre of two concentric half rings of radii R _ 1 and R _ 2 , having same linear charge

VO=V1+V2{V}_{O} = {V}_{1} + {V}_{2}

⇒VO=14πϵ0×λ1(πR1)R1+14πϵ0×λ1(πR2)R2=λ2ϵ0⇒ {V}_{O} = \dfrac{1}{4\pi{ϵ}_{0}} \times \dfrac{{\lambda}_{1}\left(\pi{R}_{1}\right)}{{R}_{1}} + \dfrac{1}{4\pi{ϵ}_{0}} \times \dfrac{{\lambda}_{1}\left(\pi{R}_{2}\right)}{{R}_{2}} = \dfrac{\lambda}{2{ϵ}_{0}}

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