Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202228 Jul 2022Evening ShiftPhysicsElectrostaticsActual

A uniform electric field E = 8 m e V m - 1 is created between two parallel plates of length 1 m as shown in figure, (where m = mass of electron and e = charge of electron). An electron enters the field symmetrically between the plates with a speed of 2 m s - 1 . The angle of the deviation θ of the path of the electron as it comes out of the field will be _____ .

Options

  1. Atan - 1 4
  2. Btan - 1 2
  3. Ctan - 1 1 3
  4. Dtan - 1 3

Correct answer

B. tan - 1 2

Step-by-step solution

Time taken by the electron to cross will be, t = 1 v x = 1 2   s . Acceleration of the electron along y axis a g = F m = E e m = 8 m e × e m = 8   m   s - 2 v y of the electron when it has crossed the capacitor will be, v y = a y t = 8 × 1 2 = 4   m   s - 1 Therefore, tan θ = v y v x = 4 2 = 2 ⇒ θ = tan - 1 2

Practice Electrostatics on Quantrex Academy →

More from Electrostatics

Two charges Q₁ = q and Q₂ = mq are placed at the points P₁(a, b) and P₂(ma, mb) , respectively, in the XY plane, where a, b 0 and m 0, 1 . If V₁ is the potential at a point in the 2026Consider an electric dipole comprising two charges +q and -q each with mass m , separated by a fixed distance d and initially at rest with its dipole moment pointing along i . A un 2026Two point charges q₁=3 , C and q₂=-4 , C are placed at points (2 i +3 j +3 k ) and ( i + j + k ) respectively. Force on charge q₂ is ________ N. ( Take 1 4 ₀ = 9 10^9 SI Units ) 2026The electric potential as a function of x, y is given by V = 5(x^2 - y^2) V. The electric field at a point (2, 3) m is __________ V/m. 2026A thin half ring of radius 35 cm is uniformly charged with a total charge of Q coulomb. If the magnitude of the electric field at centre of the half ring is 100 V/m, then the value 2026A three coulomb charge moves from the point (0, -2, -5) to the point (5, 1, 2) in an electric field expressed as E = 2x i + 3y^2 j + 4 k N/C. The work done in moving the charge is 2026A particle of charge q and mass m is projected from origin with an initial velocity v = ( v₀ 2 x + v₀ 2 y ) . There exists a uniform magnetic field B = B₀ z and a space varying ele 2026A rigid dipole undergoes a simple harmonic motion about its centre in the presence of an electric field E ₁=E₀ x . If another electric field E ₂=2E₀( y + z ) is introduced to the s 2026 Full Electrostatics list All JEE Main PYQs