Two electric dipoles of dipole moments 1 . 2 × 10 ^ - 30 cm and 2 ....

Maximum torque experienced by an electric dipole is {τ}_\max = PEsin90 °.

So, {\left|τ\right|}_\max = PE

The ratio is $\dfrac{{τ}_{1}}{{τ}_{2}} = \dfrac{{P}_{1}{E}_{1}}{{P}_{2}{E}_{2}} = \dfrac{1 . 2 \times {10}^{- 30} \times 5 \times {10}^{4}}{2 \cdot 4 \times {10}^{- 30} \times 15 \times {10}^{4}} = \dfrac{1}{6}$

Hence, the value of $x = 6$.