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JEE Main202227 Jul 2022Evening ShiftPhysicsElectrostaticsActual

A charge of 4 μ C is to be divided into two. The distance between the two divided charges is constant. The magnitude of the divided charges so that the force between them is maximum, will be:

Options

  1. A1 μ C and 3 μ C
  2. B2 μ C and 2 μ C
  3. C0 and 4 μ C
  4. D1 . 5 μ C and 2 . 5 μ C

Correct answer

B. 2 μ C and 2 μ C

Step-by-step solution

If after division, one of the charge is q the other charge will be 4 - q . The force between them can be written as, F = K q 4 - q d 2 For the force between them to be maximum, d F d q = 0 ⇒ K d 2 4 - 2 q = 0 ⇒ q = 2   μC

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