Two uniformly charged spherical conductors A and B of radii 5 mm and 10 mm are separated by a distance of 2 cm . If the spheres are connected by a conducting wire, then in equilibrium condition, the ratio of the magnitudes of the electric fields at the surface of the sphere A and B will be

Step-by-step solution

When two conductors are connected by a conducting wire, their potentials become equal. Therefore, V A = V B The potential of a spherical conductor is given by, V = k Q R ⇒ k Q A R A = k Q B R B ⇒ Q ∝ R Now the electric field near the surface of the conductor will be, E = k Q R 2 ⇒ E A E B = k Q A R A 2 k Q B R B 2 = R B R A ⇒ E A E B = 10 5 = 2 1