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JEE Main 202227 JuneEvening Shift
Exam
JEE Main
Year
2022
Date
27 June
Shift
Evening Shift
Subject
Physics
Chapter
Electrostatics

JEE Main 2022 · 27 June · Evening Shift · Physics · Electrostatics

If a charge q is placed at the centre of a closed hemispherical...

If a charge qq is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through the flat surface would be

If a charge q is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through

Options

  1. Aqε0\dfrac{q}{{ε}_{0}}
  2. Bq2ε0\dfrac{q}{2{ε}_{0}}
  3. Cq4ε0\dfrac{q}{4{ε}_{0}}
  4. Dq2πε0\dfrac{q}{2\pi{ε}_{0}}

Correct answer

B. q2ε0\dfrac{q}{2{ε}_{0}}

Step-by-step solution

If a charge q is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through

Assume a complete sphere, then flux due to a charge placed at the center of sphere is ϕ=qε0ϕ = \dfrac{q}{{ε}_{0}}

Flux through hemisphere surface is equal to flux passing through flat surface ϕ=12×qε0=q2ε0ϕ = \dfrac{1}{2} \times \dfrac{q}{{ε}_{0}} = \dfrac{q}{2{ε}_{0}}

If a charge q is placed at the centre of a closed hemispherical non-conducting surface, the total flux passing through

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