In a Vernier calipers, when both jaws touch each other, zero of the...

Least count of the Vernier calipers is given by $\text{LC} = \dfrac{1 \text{ MSD}}{\text{Number of VSD}}$.

Substituting the given values, $\text{LC} = \dfrac{1 \text{ mm}}{10} = 0.1 \text{ mm} = 0.01 \text{ cm}$.

Since the zero of the Vernier scale is shifted to the right of the zero of the main scale, the zero error is positive.

The zero error is calculated as $+ (n \times \text{LC})$, where $n$ is the coinciding Vernier division.

Given that the $7^{\text{th}}$ Vernier division coincides with a main scale reading, $n = 7$.

Zero error $= + (7 \times 0.01 \text{ cm}) = + 0.07 \text{ cm}$.

Therefore, the Vernier caliper has a $0.07 \text{ cm}$ positive zero error.

Answer: $0.07$ cm positive zero error