JEE Main20265 April 2026Morning ShiftPhysicsExperimental PhysicsActual
In a Vernier calipers, when both jaws touch each other, zero of the Vernier scale is shifted to the right of zero of the main scale and 7^ th Vernier division coincides with a main scale reading. If the value of 1 main scale division is 1 mm and there are 10 Vernier scale divisions, then the Vernier caliper has
Options
- A0.07 cm negative zero error
- B0.7 cm negative zero error
- C0.07 cm positive zero error
- D0.7 cm positive zero error
Correct answer
C. 0.07 cm positive zero error
Step-by-step solution
Least count of the Vernier calipers is given by LC = 1 MSD Number of VSD . Substituting the given values, LC = 1 mm 10 = 0.1 mm = 0.01 cm . Since the zero of the Vernier scale is shifted to the right of the zero of the main scale, the zero error is positive. The zero error is calculated as + (n LC ) , where n is the coinciding Vernier division. Given that the 7^ th Vernier division coincides with a main scale reading, n = 7 . Zero error = + (7 0.01 cm ) = + 0.07 cm . Therefore, the Vernier caliper has a 0.07 cm pos