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JEE Main202624 January 2026Evening ShiftPhysicsExperimental PhysicsActual

In a vernier callipers, 50 vernier scale divisions are equal to 48 main scale divisions. If one main scale division =0.05 ~mm , then the least count of the vernier callipers is _ _ _ _ mm.

Options

  1. A0.005
  2. B0.05
  3. C0.002
  4. D0.02

Correct answer

C. 0.002

Step-by-step solution

Given: 50 vernier divisions = 48 main divisions and 1 main division = 0.05 mm 50 vernier divisions = 48 × 0.05 = 2.4 mm 1 vernier division = 2.4/50 = 0.048 mm Least count = 1 main division - 1 vernier division = 0.05 - 0.048 = 0.002 mm

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