JEE Main202329 Jan 2023Morning ShiftPhysicsGravitationActual
Two particles of equal mass m move in a circle of radius r under the action of their mutual gravitational attraction. The speed of each particle will be :
Options
- AG m 2 r
- B4 G m r
- CG m r
- DG m 4 r
Correct answer
D. G m 4 r
Step-by-step solution
Let speed of both the particles be v . Then, gravitational force between the particles will provide the required centripetal force. Therefore, G m m 2 r 2 = m v 2 r ⇒ v = G m 4 r