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JEE Main 202226 JuneMorning Shift
Exam
JEE Main
Year
2022
Date
26 June
Shift
Morning Shift
Subject
Physics
Chapter
Gravitation

JEE Main 2022 · 26 June · Morning Shift · Physics · Gravitation

The variation of acceleration due to gravity (g) with distance (r)...

The variation of acceleration due to gravity (g)\left(g\right) with distance (r)\left(r\right) from the center of the earth is correctly represented by

(Given R=R = radius of earth)

The variation of acceleration due to gravity (g) with distance (r) from the center of the earth is correctlyThe variation of acceleration due to gravity (g) with distance (r) from the center of the earth is correctlyThe variation of acceleration due to gravity (g) with distance (r) from the center of the earth is correctlyThe variation of acceleration due to gravity (g) with distance (r) from the center of the earth is correctlyThe variation of acceleration due to gravity (g) with distance (r) from the center of the earth is correctly

Options

  1. AWhich of the following floral parts forms pericarp after fertilization?
  2. BWhich of the following floral parts forms pericarp after fertilization?
  3. CWhich of the following floral parts forms pericarp after fertilization?
  4. DWhich of the following floral parts forms pericarp after fertilization?

Correct answer

A. Which of the following floral parts forms pericarp after fertilization?

Step-by-step solution

We know that the gravitational field strength varies according to the variation of the distance of an object from the centre of the earth.

So, gravitational field strength inside the earth varies as,

g=GMrR3g = \dfrac{GMr}{{R}^{3}} if 0≤r≤R0 \le r \le R.

So, g∝rg ∝ r.

At the surface, it is maximum, g=GMR2g = \dfrac{GM}{{R}^{2}}.

Outside the earth, it varies as, g∝1r2g ∝ \dfrac{1}{{r}^{2}} for (r≥R)( r \ge R ).

So, this is the possible graph,

The variation of acceleration due to gravity (g) with distance (r) from the center of the earth is correctly

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