The elongation of a wire on the surface of the earth is 10 ^ - 4 m . The same wire of same dimensions is elongated by 6 × 10 ^ - 5 m on another planet. The acceleration due to gravity on the planet will be _____ m s ^

Correct answer: 0 Change in length ∝ Force ∝ mg mg = kx = ((YA)/(l))x Thus, x ∝ g Then, 10 ^ - 4 6 × 10 ^ - 5 = g g ^ ' ⇒ g ^ ' = 0 . 6g = 6m s ^ - 2

JEE Main 202226 JuneMorning Shift

JEE Main 2022 · 26 June · Morning Shift · Physics · Gravitation

The elongation of a wire on the surface of the earth is 10 ^ - 4 m...

The elongation of a wire on the surface of the earth is

{10}^{- 4}m

. The same wire of same dimensions is elongated by

6 \times {10}^{- 5}m

on another planet. The acceleration due to gravity on the planet will be _____

m{s}^{- 2}

. (Take acceleration due to gravity on the surface of earth

= 10{ms}^{- 2}

)

Change in length $∝$ Force $∝ mg$

$mg = kx = \left(\dfrac{YA}{l}\right)x$

Thus, $x ∝ g$

Then, $\dfrac{{10}^{- 4}}{6 \times {10}^{- 5}} = \dfrac{g}{{g}^{'}} ⇒ {g}^{'} = 0 . 6g = 6m{s}^{- 2}$