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JEE Main20238 Apr 2023Evening ShiftPhysicsKinetic Theory of GasesActual

The temperature at which the kinetic energy of oxygen molecules becomes double than its value at 27 ° C is

Options

  1. A927 ° C
  2. B327 ° C
  3. C1227 ° C
  4. D627 ° C

Correct answer

B. 327 ° C

Step-by-step solution

The kinetic energy is given by K E = f 2 k T . Let the kinetic energy be K 1 at 27   ° C and the kinetic energy be K ' at T ' temperature. As given in the question, K ' = 2 K 1 . Hence, K ' K 1 = T ' T ⇒ 2 = T ' 300 ⇒ T ' = 600   K In Celsius the temperature is T ' - 273 = 327   ° C .

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