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JEE Main 20244 AprilMorning Shift
Exam
JEE Main
Year
2024
Date
4 April
Shift
Morning Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2024 · 4 April · Morning Shift · Physics · Magnetic Effects of Current

The magnetic field existing in a region is given by B =0.2(1+2 x) k...

The magnetic field existing in a region is given by B⃗=0.2(1+2x)k^ T\vec{B}=0.2(1+2 x) \hat{k} \mathrm{~T}. A square loop of edge 50 cm50 \mathrm{~cm} carrying 0.5 A current is placed in x−yx-y plane with its edges parallel to the x−yx-y axes, as shown in figure. The magnitude of the net magnetic force experienced by the loop is_____ mN\mathrm{mN}. The magnetic field existing in a region is given by B =0.2(1+2 x) k ~T . A square loop of edge 50 ~cm carrying 0.5 A

Correct answer

0

Step-by-step solution

Force on segment parallel to x\mathrm{x}-axis will cancel each other. Hence Fnet\mathrm{F}_{\mathrm{net}} will be due to portion parallel to yy-axis. F=0.5×0.5×6×0.2−0.5×0.5×0.2×5=0.5×0.5×0.2=0.25×0.2=50×10−3 N=50mN\begin{aligned} & F=0.5 \times 0.5 \times 6 \times 0.2-0.5 \times 0.5 \times 0.2 \times 5 \\ & =0.5 \times 0.5 \times 0.2 \\ & =0.25 \times 0.2 \\ & =50 \times 10^{-3} \mathrm{~N} \\ & =50 \mathrm{mN} \end{aligned}
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