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JEE Main 20241 FebruaryEvening Shift
Exam
JEE Main
Year
2024
Date
1 February
Shift
Evening Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2024 · 1 February · Evening Shift · Physics · Magnetic Effects of Current

A moving coil galvanometer has 100 turns and each turn has an area...

A moving coil galvanometer has 100100 turns and each turn has an area of 2.0cm2.2 . 0{cm}^{2} . The magnetic field produced by the magnet is 0.01T0 . 01T and the deflection in the coil is 0.050 . 05 radian when a current of 10mA10mA is passed through it. The torsional constant of the suspension wire is x×10−5N−m/rad.x \times {10}^{- 5}N - m / rad . The value of xx is ______ .

Correct answer

0

Step-by-step solution

Torque produced in a moving coil galvanometer is, τ=BINAsinϕτ = BINAsinϕ.

Let torsional constant of the suspension wire be CC, then Cθ=BINAsin90°C\theta = BINAsin90 °

⇒C=BINAθ=0.01×10×10−3×100×2×10−40.05⇒ C = \dfrac{BINA}{\theta} = \dfrac{0 . 01 \times 10 \times {10}^{- 3} \times 100 \times 2 \times {10}^{- 4}}{0 . 05}

=4×10−5N−m/rad.= 4 \times {10}^{- 5}N - m / rad .

Therefore, x=4x = 4.

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