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JEE Main 202427 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
27 January
Shift
Morning Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2024 · 27 January · Morning Shift · Physics · Magnetic Effects of Current

A proton moving with a constant velocity passes through a region of...

A proton moving with a constant velocity passes through a region of space without any change in its velocity. If E→\overset{\to}{E} and B→\overset{\to}{B} represent the electric and magnetic fields respectively, then the region of space may have :
(A) E=0,B=0E = 0, B = 0; (B) E=0,B≠0E = 0, B \ne 0; (C) E≠0,B=0E \ne 0, B = 0; (D) E≠0,B≠0E \ne 0, B \ne 0

Choose the most appropriate answer from the options given below :

Options

  1. A(A), (B) and (C) only
  2. B(A), (C) and (D) only
  3. C(A), (B) and (D) only
  4. D(B), (C) and (D) only

Correct answer

C. (A), (B) and (D) only

Step-by-step solution

Net force on proton inside an electric and a magnetic field is given by

F→e+F→m=qE→+q(v→×B→)...(1)\overset{\to}{F}e + \overset{\to}{F}m = q\overset{\to}{E} + q\left(\overset{\to}{v} \times \overset{\to}{B}\right) . . . \left(1\right)

If both E→\overset{\to}{E} and B→\overset{\to}{B} are zero, then F→e\overset{\to}{F}e and F→m\overset{\to}{F}m both are zero. Hence, velocity may remain constant. Therefore, option (A) is correct.

If E=0,B≠0E = 0, B \ne 0, but velocity is parallel or antiparallel to the magnetic field, then also F→e\overset{\to}{F}e and F→m\overset{\to}{F}m both are zero. Hence, option (B) is also correct.

If E≠0,B≠0E \ne 0, B \ne 0, but F→e+F→m=0\overset{\to}{F}e + \overset{\to}{F}m = 0, then also velocity may remain constant. Thus, option (D) is also correct.

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