An electron in a hydrogen atom revolves around its nucleus with a speed of 6 . 76 × 10 6 m s – 1 in an orbit of radius 0 . 52 Å . The magnetic field produced at the nucleus of the hydrogen atom is _______ T .

Step-by-step solution

The magnetic field due to the electron is given by B = μ 0 q v sin 90 ° 4 π r 2 The given data is v = 6 . 76 × 10 6   m   s - 1 r = 0 . 52 × 10 - 10   m Thus, the magnetic field is B = 10 - 7 × 1 . 6 × × 10 - 19 × 6 . 76 × 10 6 0 . 52 × 0 . 52 × 10 - 20 = 40   T