Two long parallel wires carrying currents 8 A and 15 A in opposite directions are placed at a distance of 7 cm from each other. A point P is at equidistant from both the wires such that the lines joining the point P to the wires are perpendicular to each other. The magnitude of magnetic field at P is ______ × 10 - 6 T . (Given: 2 = 1 . 4 )

Step-by-step solution

Here, the magnetic fields produced by the two wires will be perpendicular to one another. Magnetic field due to wire carrying current 8   A is B 1 = μ 0 i 1 2 π d and magnetic field due to wire carrying current 15   A is B 2 = μ 0 i 2 2 π d The net magnetic field is B net = B 1 2 + B 2 2 = μ 0 2 π d i 1 2 + i 2 2 = 4 π × 10 - 7 2 π × 7 2 × 10 - 2 × 8 2 + 15 2   d = 7 2   cm = 68 × 10 - 6     T .