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JEE Main202324 Jan 2023Morning ShiftPhysicsMagnetic Effects of CurrentActual

Two long straight wires P and Q carrying equal current 10 A each were kept parallel to each other at 5 cm distance. Magnitude of magnetic force experienced by 10 cm length of wire P is F 1 . If distance between wires is halved and currents on them are doubled, force F 2 on 10 cm length of wire P will be:

Options

  1. A8 F 1
  2. B10   F 1
  3. CF 1 8
  4. DF 1 10

Correct answer

A. 8 F 1

Step-by-step solution

As we know, force per unit length between two parallel straight wires is given by, F = μ 0 i 1 i 2 2 π d . Therefore, required ratio F 1   F 2 = μ 0 ( 10 ) 2 2 π ( 5 × 10 - 2 ) μ 0 ( 20 ) 2 2 π 5 2 × 10 - 2 = 1 8 ⇒ F 2 = 8 F 1

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