Two parallel, long wires are kept 0 . 20 m apart in vacuum, each carrying current of x A in the same direction. If the force of attraction per meter of each wire is 2 × 10 - 6 N , then the value of x is approximately

Step-by-step solution

Force per unit length between two parallel wires is F l = μ 0 i 1 i 2 2 π d Here, i 1 = i 2 = i and F l = 2 × 10 - 6   N Then, 2 × 10 - 6 = 4 π 2 × 10 - 7 i 2 2 π × 0 . 2 ⇒ i 2 = 2 ⇒ i = 1 . 4   A Hence, x = 1 . 4 .