Two parallel, long wires are kept 0 . 20m apart in vacuum, each...

Force per unit length between two parallel wires is $\dfrac{F}{l} = \dfrac{{\mu}_{0}{i}_{1}{i}_{2}}{2\pid}$

Here, ${i}_{1} = {i}_{2} = i$ and $\dfrac{F}{l} = 2 \times {10}^{- 6}N$

Then, $2 \times {10}^{- 6} = \dfrac{4{\pi}^{2} \times {10}^{- 7}{i}^{2}}{2\pi \times 0 . 2}$

$⇒ {i}^{2} = \sqrt{2} ⇒ i = 1 . 4A$

Hence, $x = 1 . 4$.