A uniform conducting wire of length is 24a, and resistance R is...

$4a{n}_{1} = 24a$

thus ${n}_{1} = 6$ turns

$3{an}_{2} = 24a ⇒ {n}_{2} = 8$ turns

$\dfrac{{M}_{1}}{{M}_{2}} = \dfrac{{n}_{1}i{A}_{1}}{{n}_{2}i{A}_{2}} = \dfrac{6 \times {a}^{2}}{8 \times {a}^{2} \times \dfrac{\sqrt{3}}{4}} = \dfrac{\sqrt{3}}{1}$

$\dfrac{{M}_{2}}{{M}_{1}} = \dfrac{1}{\sqrt{3}} = \dfrac{1}{\sqrt{y}}$

$y = 3$