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JEE Main202126 Aug 2021Evening ShiftPhysicsMagnetic Effects of CurrentActual

If the maximum value of accelerating potential provided by a radio frequency oscillator is 12 kV . The number of revolution made by a proton in a cyclotron to achieve one sixth of the speed of light is: m p = 1 . 67 × 10 - 27   kg ,   e = 1 . 6 × 10 - 19   C , Speed of light = 3 × 10 8   m   s - 1

Correct answer

543

Step-by-step solution

From the conservation of energy, 2 n e V = 1 2 m v 2 ⇒ 2 n × 12 × 10 3 × 1 . 6 × 10 - 19 = 1 2 × 1 . 67 × 10 - 27 × 5 × 10 7 2 ⇒ n = 543

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