JEE Main 20206 SeptemberMorning Shift

Exam: JEE Main
Year: 2020
Date: 6 September
Shift: Morning Shift
Subject: Physics
Chapter: Magnetic Effects of Current

JEE Main 2020 · 6 September · Morning Shift · Physics · Magnetic Effects of Current

A particle of charge q and mass m is moving with a velocity - v ^ i...

A particle of charge

q

and mass

m

is moving with a velocity

- v\overset{^}{i} ( v \ne 0 )

towards a large screen placed in the

Y - Z

plane at distance d. If there is magnetic field

\overset{\to}{B} = {B}_{0}\overset{^}{k},

the minimum value of

v

for which the particle will not hit the screen is : A particle of charge q and mass m is moving with a velocity - v ^ i ( v ≠ 0 ) towards a large screen placed in the Y -

A particle of charge q and mass m is moving with a velocity - v ^ i ( v ≠ 0 ) towards a large screen placed in the Y -

Options

A $\dfrac{{qdB}_{0}}{3m}$
B $\dfrac{2qd{B}_{0}}{m}$
C $\dfrac{qd{B}_{0}}{m}$
D $\dfrac{{qdB}_{0}}{2m}$

Correct answer

C. $\dfrac{qd{B}_{0}}{m}$

Step-by-step solution

A particle of charge q and mass m is moving with a velocity - v ^ i ( v ≠ 0 ) towards a large screen placed in the Y -

The radius of circular path in given magnetic field is

$r = d = \dfrac{mv}{q{B}_{0}}$

so $v = \dfrac{q{B}_{0}d}{m}$

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