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JEE Main 20206 SeptemberMorning Shift
Exam
JEE Main
Year
2020
Date
6 September
Shift
Morning Shift
Subject
Physics
Chapter
Magnetic Effects of Current

JEE Main 2020 · 6 September · Morning Shift · Physics · Magnetic Effects of Current

An electron is moving along + x direction with a velocity of 6 × 10...

An electron is moving along +x+ x direction with a velocity of 6×106ms−16 \times {10}^{6}{ms}^{- 1}. It enters a region of uniform electric field of 300V/cm300V / cm pointing along +y+ y direction. The magnitude and direction of the magnetic field set up in this region such that the electron keeps moving along the x direction will be:

Options

  1. A3×10−4T,3 \times {10}^{- 4}T, along +z+ z direction
  2. B5×10−3T,5 \times {10}^{- 3}T, along −z- z direction
  3. C5×10−3T,5 \times {10}^{- 3}T, along +z+ z direction
  4. D3×10−4T,3 \times {10}^{- 4}T, along −z- zdirection

Correct answer

C. 5×10−3T,5 \times {10}^{- 3}T, along +z+ z direction

Step-by-step solution

q∨B=qEq ∨ B = qE

B=EV=300006×106=5×103TB = \dfrac{E}{V} = \dfrac{30000}{6 \times {10}^{6}} = 5 \times {10}^{3}T

Magnetic force F=q(V→×B→)F = q ( \overset{\to}{V} \times \overset{\to}{B} )

So Ans.5×103T5 \times {10}^{3}T ,along +Z direction

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