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JEE Main 20257 AprilEvening Shift
Exam
JEE Main
Year
2025
Date
7 April
Shift
Evening Shift
Subject
Physics
Chapter
Mechanical Properties of Fluids

JEE Main 2025 · 7 April · Evening Shift · Physics · Mechanical Properties of Fluids

A capillary tube of radius 0.1 mm is partly dipped in water...

A capillary tube of radius 0.1 mm is partly dipped in water (surface tension 70dyn/cm70 \mathrm{dyn} / \mathrm{cm} and glass water contact angle ≃0∘\simeq 0^{\circ}) with 30∘30^{\circ} inclined with vertical. The length of water risen in the capillary is ________ cm.
(\left(\right. Take g=9.8 m/s2)\left.\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2\right)A capillary tube of radius 0.1 mm is partly dipped in water (surface tension 70 dyn / cm and glass water contact angle

Options

  1. A825\frac{82}{5}
  2. B572\frac{57}{2}
  3. C715\frac{71}{5}
  4. D685\frac{68}{5}

Correct answer

A. 825\frac{82}{5}

Step-by-step solution

A capillary tube of radius 0.1 mm is partly dipped in water (surface tension 70 dyn / cm and glass water contact angle
h=2 Tcos⁡θρgr=2×70×11×980×10−2 h=1007 cmsin⁡60∘=hℓℓ=h×23ℓ=1007×23=2007×3=16.49 cm\begin{aligned} & \mathrm{h}=\frac{2 \mathrm{~T} \cos \theta}{\rho \mathrm{gr}}=\frac{2 \times 70 \times 1}{1 \times 980 \times 10^{-2}} \\ & \mathrm{~h}=\frac{100}{7} \mathrm{~cm} \\ & \sin 60^{\circ}=\frac{\mathrm{h}}{\ell} \\ & \ell=\frac{\mathrm{h} \times 2}{\sqrt{3}} \\ & \ell=\frac{100}{7} \times \frac{2}{\sqrt{3}} \\ & =\frac{200}{7 \times \sqrt{3}} \\ & =16.49 \mathrm{~cm}\end{aligned}
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